## Contents

- 1 Theorem
- 1.1 First Supplement to Law of Quadratic Reciprocity
- 1.2 Second Supplement to Law of Quadratic Reciprocity

- 2 Proof
- 3 Also known as
- 4 Historical Note
- 5 Sources

## Theorem

Let $p$ and $q$ be distinct odd primes.

Then:

- $\paren {\dfrac p q} \paren {\dfrac q p} = \paren {-1}^{\dfrac {\paren {p - 1} \paren {q - 1} } 4}$

where $\paren {\dfrac p q}$ and $\paren {\dfrac q p}$ are defined as the Legendre symbol.

An alternative formulation is:$\paren {\dfrac p q} = \begin{cases}\quad \paren {\dfrac q p} &: p \equiv 1 \lor q \equiv 1 \pmod 4 \\-\paren {\dfrac q p} &: p \equiv q \equiv 3 \pmod 4\end{cases}$

The fact that these formulations are equivalent is immediate.

This fact is known as the **Law of Quadratic Reciprocity**, or **LQR** for short.

### First Supplement to Law of Quadratic Reciprocity

$\quad \paren {\dfrac {-1} p} = \paren {-1}^{\paren {p - 1} / 2} = \begin {cases}+1 &: p \equiv 1 \pmod 4 \\-1 &: p \equiv 3 \pmod 4\end {cases}$

### Second Supplement to Law of Quadratic Reciprocity

$\quad \paren {\dfrac 2 p} = \paren {-1}^{\paren {p^2 - 1} / 8} = \begin {cases}+1 &: p \equiv \pm 1 \pmod 8 \\-1 &: p \equiv \pm 3 \pmod 8\end {cases}$

## Proof

Let $p$ and $q$ be distinct odd primes.

Consider the rectangle in the $x y$ plane with vertices at $\tuple {0, 0}, \tuple {\dfrac p 2, 0}, \tuple {\dfrac p 2, \dfrac q 2}, \tuple {0, \dfrac q 2}$.

The number of lattice points inside this rectangle is $\dfrac {p - 1} 2 \times \dfrac {q - 1} 2$.

Consider the diagonal from $\tuple {0, 0}$ to $\tuple {\dfrac p 2, \dfrac q 2}$.

This has the equation:

- $y = \dfrac q p x$

Aiming fora contradiction, suppose there were a lattice point $\tuple {a, b}$ on the diagonal.

Then:

- $b = \dfrac q p a$

But as $p$ and $q$ are distinct primes, this would mean:

- $p$ divides $a$

and:

- $q$ divides $b$

This means that $\tuple {a, b}$ has to be outside the rectangle.

So there are no lattice points on the diagonal inside the rectangle.

Let $A$ and $B$ be the triangular regions inside the rectangle lying respectively above and below the diagonal.

Let $k \in \Z: 0 < k < \dfrac p 2$.

The number of lattice points in $B$ which lie directly above the point $\tuple {k, 0}$ is:

- $\floor {\dfrac q p k}$

where $\floor {\dfrac q p k}$ is the floor of $\dfrac q p k$.

So the total number of lattice points in $B$ is given by:

- $\ds N_B = \sum_{k \mathop = 1}^{\frac{p - 1} 2} \floor {\dfrac q p k}$

Let $\map \alpha {q, p}$ be defined as:

- $\ds \map \alpha {q, p} = \sum_{k \mathop = 1}^{\frac {p - 1} 2} \floor {\dfrac q p k}$

In the same way, by counting the lattice points to the right of $\tuple {0, k}$, the total number of lattice points in $A$ is given by:

- $N_A = \map \alpha {p, q}$

Now the total number of lattice points in the rectangle is $N_A + N_B$.

But this is also equal to:

- $\dfrac {p - 1} 2 \times \dfrac {q - 1} 2 = \dfrac {\paren {p - 1} \paren {q - 1} } 4$

So we have that:

- $\map \alpha {p, q} + \map \alpha {q, p} = \dfrac {\paren {p - 1} \paren {q - 1} } 4$

The fact that these counts are equal relies upon the fact that there are no lattice points on the diagonal, as demonstrated above.

Now we invoke Eisenstein's Lemma:

- $\paren {\dfrac a p} = \paren {-1}^{\map \alpha {a, p} }$

So this gives us:

\(\ds \paren {\frac p q} \paren {\frac q p}\) | \(=\) | \(\ds \paren {-1}^{\map \alpha {p, q} } \times \paren {-1}^{\map \alpha {q, p} }\) | ||||||||||||

\(\ds \) | \(=\) | \(\ds \paren {-1}^{\map \alpha {p, q} + \map \alpha {q, p} }\) | ||||||||||||

\(\ds \) | \(=\) | \(\ds \paren {-1}^{\frac {\paren {p - 1} \paren {q - 1} } 4}\) |

which is LQR.

$\blacksquare$

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## Also known as

The **Law of Quadratic Reciprocity** is also known as the **law of Gaussian reciprocity**, after Carl Friedrich Gauss.

## Historical Note

The Law of Quadratic Reciprocity was investigated by Leonhard Paul Euler who stated it imperfectly and failed to find a proof.

Adrien-Marie Legendre first stated it correctly, but his attempted $\text {1785}$ proof of it was incorrect.

Carl Friedrich Gauss first became aware of this result, and found a correct proof. He wrote this up in $\text {1798}$ and published it in his Disquisitiones Arithmeticae in $\text {1801}$.

The proof as given here was found by Ferdinand Eisenstein and published in $\text {1844}$.

## Sources

- 1844:F.G. Eisenstein:
*Geometrischer Beweis des Fundamentaltheorems für die quadratischen Reste*(J. reine angew. Math.**Vol. 28**:pp. 246 – 248) - 1989:Ephraim J. Borowskiand Jonathan M. Borwein: Dictionary of Mathematics... (previous)... (next):
**quadratic reciprocity**or**Gaussian reciprocity** - 1997:Donald E. Knuth: The Art of Computer Programming: Volume 1: Fundamental Algorithms(3rd ed.)... (previous)... (next): $\S 1.2.4$: Integer Functions and Elementary Number Theory: Exercise $47 \ \text{d)}$
- 1998:David Nelson: The Penguin Dictionary of Mathematics(2nd ed.)... (previous)... (next):
**quadratic reciprocity, law of** - 2008:David Nelson: The Penguin Dictionary of Mathematics(4th ed.)... (previous)... (next):
**quadratic reciprocity, law of** - 2008:Ian Stewart: Taming the Infinite... (previous)... (next): Chapter $7$: Patterns in Numbers: Gauss